Question: Mark:5+5+5+5 Consider the following Context Free Grammar (CFG) S → aY | Ybb | Y X → Λ | a Y → aXY | bb | XXa a) Is the CFG ambiguous, if Yes then justify your answer. b) Draw a Total Language Tree (TLT) for the given CFG. c) Convert the CFG into CNF. d) Build the PDA corresponding to the CFG (in CNF) of part (c).
Solution:-
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Question: Mark:5+5+5+5 Consider the following Context Free Grammar (CFG)
S → aY | Ybb | Y
X → Λ | a
Y → aXY | bb | XXa a) Is the CFG ambiguous, if Yes then justify your answer. b) Draw a Total Language Tree (TLT) for the given CFG. c) Convert the CFG into CNF. d) Build the PDA corresponding to the CFG (in CNF) of part (c).
Part a
this CFG Is not ambiguous because any string in not shown two derivation tree.
Part b
second is its total language tree may be arbitrary wide as well as infinity long.
Part c
CFG Into CNF removing null and unit production
s-> Ay| yBB | b
x-> a | a
y-> Axy | Ax |BB | xxa| xx | xA | a
A->a
B->b
part d
This is wrong.I was not able to convert it into CNF, but I am very close to do it so!
S->aY|Ybb|Y
X->^|a
Y->aXY|bb|XXa
null production
Y->aY|bb|Xa|a
after removing null production
S->aY|Ybb|Y
X->a
Y->aY|bb|Xa|a
Unit production
S->Y
S->Y->aY gives S->abb (Y->bb)
S->Y->aY gives S->aa (Y->a)
S->Y->aY->aXa gives S->aaa (X->a)
New CFG will be
S->aY|Ybb|abb|aa|aaa
X->a
Y->aY|bb|Xa|a
(i am stuck here)
Question: Mark:5+5+5+5 Consider the following Context Free Grammar (CFG)
S → aY | Ybb | Y
X → Λ | a
Y → aXY | bb | XXa a) Is the CFG ambiguous, if Yes then justify your answer. b) Draw a Total Language Tree (TLT) for the given CFG. c) Convert the CFG into CNF. d) Build the PDA corresponding to the CFG (in CNF) of part (c).
Part a
this CFG Is not ambiguous because any string in not shown two derivation tree.
Part b
second is its total language tree may be arbitrary wide as well as infinity long.
Part c
CFG Into CNF removing null and unit production
s-> Ay| yBB | b
x-> a | a
y-> Axy | Ax |BB | xxa| xx | xA | a
A->a
B->b
part d
This is wrong.I was not able to convert it into CNF, but I am very close to do it so!
S->aY|Ybb|Y
X->^|a
Y->aXY|bb|XXa
null production
Y->aY|bb|Xa|a
after removing null production
S->aY|Ybb|Y
X->a
Y->aY|bb|Xa|a
Unit production
S->Y
S->Y->aY gives S->abb (Y->bb)
S->Y->aY gives S->aa (Y->a)
S->Y->aY->aXa gives S->aaa (X->a)
New CFG will be
S->aY|Ybb|abb|aa|aaa
X->a
Y->aY|bb|Xa|a
(i am stuck here)
Please do make changes in these assignment otherwise every one who copy this assignment as it is will awarded zero marks
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